In an experiment to determine the gravitational acceleration $g$ of a place with the help of a simple pendulum, the measured time period squared is plotted against the string length of the pendulum in the figure. What is the value of $g$ at the place?

Question

TestHub · Accepted Answer

T = 2 π L g ⇒ g = 4 π 2 L T 2 T 2 L = 4 π 2 g = tanθ = slope of graph ⇒ g = 4 π 2 tanθ ∵ tanθ = 8 − 2 2 − 0.5 = 6 1.5 = 4 ⇒ g = 4 π 2 4 = ( 3.14 ) 2 = π 2 = 3 . 1 4 2 = 9 . 8 7 m s - 2

Physics - Practical physics Question with Solution | TestHub

Options:

Doubts & Discussion