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PhysicsErrorMiscellaneousMedium2 minPYQ_2021
PhysicsMediumassertion reason

Assertion A: If in five complete rotations of the circular scale, the distance travelled on the main scale of the screw gauge is 5 mm and there are 50 total divisions on a circular scale, then the least count is 0.001 cm.

Reason R:
Least Count = Pitch  Total divisions on circular scale 
In the light of the above statements, choose the most appropriate answer from the options given below.

Answer:
A
Solution:

Least count = Pitch  total division on circular scale 
In 5 revolution, distance travel, 5 mm.

In 1 revolution, it will travel 1 mm.
So the least count =150=0.02

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous
2mℹ️ Source: PYQ_2021

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