Home

Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsExperimental & Practical PhysicsEasy2 minPYQ_2006

PhysicsEasysingle choice

The circular scale of a screw gauge has 50 divisions and pitch of $0.5 mm$ . Find the diameter of sphere. Main scale reading is 2 .

Question diagram: The circular scale of a screw gauge has 50 divisions and pit

Options:

Answer:

Solution:

Least count $LC = \frac{Pitch}{Number of divisions on circular scale} = \frac{0.1}{50}$ $= 0.01 mm$ Now, diameter of ball $= (2 \times 0.5 mm) + (25 - 5) (0.01) = 1.2 mm$

Stream:JEE_ADVSubject:PhysicsTopic:Practical physicsSubtopic:Experimental & Practical Physics

⏱ 2mℹ️ Source: PYQ_2006

Doubts & Discussion

Loading discussions...