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PhysicsPractical physicsExperimental & Practical PhysicsMedium2 minPYQ_2021
PhysicsMediumnumerical

Student A and student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0.322 cm. The absolute value of the difference between the final circular scale readings observed by the students A and B is _______.

[Figure shows position of reference O when jaws of screw gauge are closed]

Given pitch =0.1 cm.

Question diagram: Student A and student B used two screw gauges of equal pitch
Answer:
13.00
Solution:

For A,

Reading =MSR+CSR+Error

0.322=0.300+CSR+5×LC

0.322=0.300+CSR+0.005

CSR=0.017

For B

Reading =MSR+CSR+Error

0.322=0.200+CSR+0.092

CSR=0.030

Difference =0.030-0.017=0.013 cm

Division on circular scale =0.0130.001=13

Stream:JEESubject:PhysicsTopic:Practical physicsSubtopic:Experimental & Practical Physics
2mℹ️ Source: PYQ_2021

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