A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 c m and a stopwatch with 1 s resolution measures the time

Question

A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 c m and a stopwatch with 1 s resolution measures the time taken for 40 oscillations to be 50 s . The accuracy in g is:

TestHub · Accepted Answer

Time period of the simple pendulum, T = 2 π l g ⇒ g = 4 π 2 l T 2 ∆ g g = 2 ∆ T T + ∆ L L ⇒ ∆ g g = 2 1 50 + 0.1 25.0 ⇒ ∆ g g = 4.4 %

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