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PhysicsPractical physicsMiscellaneousMedium2 minPYQ_2020

PhysicsMediumsingle choice

A glass convex lens is of refractive index $1 \cdot 55$ with both faces of same radius of curvature. What will be the radius of curvature if focal length is to be $20 cm$ ?

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Answer:

Solution:

Lens maker's formula, $\frac{1}{f} = (μ - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}})$ Here, $f = 20 cm, μ = 1.55, R_{1} = R, R_{2} = - R$ $\frac{1}{20} = (1.55 - 1) (\frac{1}{R} - \frac{1}{( - R )}) or \frac{1}{20} = 0.55 \times \frac{2}{R} \Rightarrow R = 1.1 \times 20 = 22 cm$

Stream:MHT_CETSubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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