The maximum percentage error in the measurment of density of a wire is [Given, mass of wire $= (0.60 \pm 0.003) g$
radius of wire $= (0.50 \pm 0.01) cm$
length of wire $= (10.00 \pm 0.05) cm]$

Question

The maximum percentage error in the measurment of density of a wire is [Given, mass of wire = ( 0.60 ± 0.003 ) g radius of wire = ( 0.50 ± 0.01 ) cm length of wire = ( 10.00 ± 0.05 ) cm ]

TestHub · Accepted Answer

​ d = vol. m ​ = π R 2 ℓ m ​ ⇒ ρ d ρ ​ = m dm ​ + R 2 dR ​ + ℓ d ℓ ​ ⇒ ρ d ρ ​ = ( 0.6 0.003 ​ + 0.5 2 × 0.01 ​ + 10 0.05 ​ ) 100 = 5% ​

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