The following observations were taken for determining surface tension T of water by capillary method: diameter of capillary, D = 1.25 × 10 - 2 m rise of water, h = 1.45 × 10 - 2 m Using g = 9.80 m s -

Question

The following observations were taken for determining surface tension $T$ of water by capillary method:

diameter of capillary, $D = 1.25 \times 10^{- 2} m$

rise of water, $h = 1.45 \times 10^{- 2} m$

Using $g = 9.80 m s^{- 2}$ and the simplified relation $T = \frac{r h g}{2} \times 10^{3} N m^{- 1}$ the possible error in surface tension is closest to:

TestHub · Accepted Answer

Percentage error in surface tension ∆ T T = ∆ r r + ∆ h h ∆ r r = ∆ D D = 0.01 1 .25 ∆ h h = 0.01 1.45 ∴ % e r r o r i n T = ∆ T T × 100 = 0.01 1.25 + 0.01 1.45 × 100 = 1.489 ≈ 1.5

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