Start Free Mock LoginAlready registered? Login here

Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionEasy2 minQB

PhysicsEasynumerical

A book of weight $20 N$ is pressed between two hands and each hand exerts a force of $40 N$ . If the book just starts to slide down. What is the value of the coefficient of friction?

Answer:

0.25

Solution:

Block is in horizontal equilibrium. In the vertical direction, it is in limiting equilibrium.

$μ_{s} = \frac{F_{s}}{R} = \frac{m g}{R} = \frac{20}{40} = 0.5$

$m g = 2 f r_{1} = 2 μ F$

$μ = \frac{m g}{2 F}$ $= \frac{20}{2 \times 40} = 0.25$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...