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Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionMedium2 minQB

PhysicsMediumsingle choice

In the arrangement shown in figure, coefficient of friction between the two blocks is $μ = 1/2$ . The force of friction acting between the two blocks is

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Answer:

Solution:

Acceleration of system $a = \frac{20 - 2}{2 + 4} = 3 ms^{- 2}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

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