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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMEasy2 minQB

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Passage / Comprehension

A shot putter with a mass of 80 kg pushes the iron ball of mass of 6 kg from a standing position, accelerating it uniformly from rest at an angle of 45° with the horizontal during a time interval of 0.1 seconds. The ball leaves his hand when it is 2 m high above the level ground and hits the ground 2 seconds later.

The minimum value of the static coefficient of friction if the shot putter does not slip during the shot is closest to

Options:

Answer:

Solution:

$- 2 = \frac{U}{2} (2) - \frac{1}{2} \times 10 \times 82 \times 2$

$∴ U = 92 m / s .$

from $A_{0}, V = u + at$

$92 = 0 + a (0.1)$

$∴ a = 902 m / s^{2}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: QB

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