A block of mass 10 kg is kept on a smooth horizontal surface as shown. A force F is acted at an angle of 5 3 ∘ with horizontal. Find the value of F (in N) such that block moves with maximum acceleration on smooth horizontal surface.

For maximum acceleration, F cos 5 3 ∘ = ma F sin 5 3 ∘ = mg {just leaves contact}

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Physics - NLM Question with Solution | TestHub

PhysicsNLMChallenging application of NLMHard2 minQB

PhysicsHardnumerical

A block of mass 10 kg is kept on a smooth horizontal surface as shown. A force F is acted at an angle of $5 3^{\circ}$ with horizontal. Find the value of F (in N) such that block moves with maximum acceleration on smooth horizontal surface.

Answer:

125.00

Solution:

For maximum acceleration,

$F cos 5 3^{\circ} = ma$

$F sin 5 3^{\circ} = mg$ {just leaves contact}

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Challenging application of NLM

⏱ 2mℹ️ Source: QB

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