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PhysicsNLMSimple Application of NLMMedium2 minQB

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Two blocks whose sum of masses is 1 kg were arranged as shown. Acceleration of blocks is twice, when A is hanging that of when B is hanging, the mass of A is (neglect friction)

Options:

Answer:

Solution:

Total mass is 1 kg, so the system mass is 1 kg in both cases.

A hanging: $a_{1} = \frac{m _{A} g}{1}$ . B hanging: $a_{2} = \frac{m _{B} g}{1}$ .

Given $a_{1} = 2 a_{2}$ so $m_{A} = 2 m_{B}$ . With $m_{A} + m_{B} = 1$ : $\frac{3 m _{B}}{1} = 1 \Rightarrow m_{B} = \frac{1}{3}, m_{A} = \frac{2}{3} kg$ . Answer: (D).

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: QB

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