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PhysicsNLMFrictionMedium2 minQB

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A force $F = 2 \hat{i} + 6 \hat{j}$ acts on block shown. The force of friction acting on the block is :

Answer:

Solution:

$F_{x} = 2 N$

$F_{y} = 6 N$

$N = m g - F_{y} = 10 - 6 = 4 N$

$f_{m a x} = μ N = 0.8 \times 4 = 3.2 N$

$F_{x} = 2 < f_{m a x}$

$f = - 2 \hat{i} N$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

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