Figure shows a block of mass m in contact with wedge of mass M. Force F is such | TestHub

PhysicsHardmultiple choice

Figure shows a block of mass m in contact with wedge of mass M. Force F is such that block is just stationary relative to wedge. Contact surface between block and wedge is rough whereas ground is smooth. Coefficient of friction is $μ$ . Mark the CORRECT statement.

Options:(select one or more)

Answer:

A, B, C

Solution:

Since, block is stationary relative to wedge hence they both must be moving with same acceleration. $So F = (m + M) a \Rightarrow a = \frac{F}{m + M}$ ......(i)

Drawing FBD of block

$F - N = ma$ ......(ii)

FBD of wedge

N = Ma .......(iii)

$N = \frac{MF}{m + M}$

For block to stay at rest :

$μ N = mg μ Ma = mg μ M \frac{F}{m + M} = mg \Rightarrow F = \frac{mg}{μ M} [m + M]$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

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