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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A marble block of mass $2 kg$ lying on ice when given a velocity of $6 {m s}^{- 1}$ is stopped by friction in $10 s$ . Then the coefficient of friction is

Options:

Answer:

Solution:

Let coefficient of friction be $μ$ , and then retardation will be $μ g$ .

From equation of motion, $v = u + a t$

$\Rightarrow 0 = 6 - μ g \times 10$

$\Rightarrow μ = \frac{6}{100} = 0.06$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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