Consider the shown arrangement: the coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and the horizontal surface. If a horizontal force of 12 N is app

Question

Consider the shown arrangement: the coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and the horizontal surface. If a horizontal force of 12 N is applied on the 2 kg block as shown in the figure, acceleration of the 4 kg block would be: (Take g = 10 m/s²)

TestHub · Accepted Answer

Maximum friction between the blocks = 0.5 × 2 × 10 = 10 N . If they move together a = 6 12 ​ = 2 m/ s 2 , needing friction 4 × 2 = 8 N < 10 N on the 4 kg block - so they do move together and the 4 kg block accelerates at 2 m/s². Option B.

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