A particle P is projected normal to the incline at t = 0 from a point on the surface of a smooth inclined plane as shown in the figure. Simultaneously another particle Q is released from rest on the s

Question

A particle P is projected normal to the incline at $t = 0$ from a point on the surface of a smooth inclined plane as shown in the figure. Simultaneously another particle Q is released from rest on the smooth inclined plane from the same position. P and Q collide after $t = 4$ seconds. Then choose the CORRECT Option(s). (Take $g = 10 m / s^{2}$ )

TestHub · Accepted Answer

Acceleration of particle P and Q along the incline is same, Acceleration of particle P perpendicular to the incline plane is 10 cos 6 0 ∘ = 5 m / s 2 . So, V P ​ − 5 ( 2 ) = 0 ∴ V P ​ = 10 m / s

Physics - Kinematics Question with Solution | TestHub

Options:

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JEE Main 2027 (Class 12)