Physics - Kinematics Question with Solution | TestHub

Horizontal component of velocity

${\text{u}}_{\text{H}}={\text{u cos 60}}^{\text{o}}=\frac{\text{u}}{2}$

$\therefore \text{AC}=\left({\text{u}}_{\text{H}}\right)\text{t}=\frac{\text{u}\text{t}}{2}$



and$\mathrm{AB} = \mathrm{AC} \sec 30°$

$=\left(\frac{\text{ut}}{2}\right)\left(\frac{2}{\sqrt{3}}\right)=\frac{\text{ut}}{\sqrt{3}}$