Three blocks are arranged on a horizontal table ABCD as shown in the figure. The strings and pulleys are massless and both the pulleys stand vertical. The strings connecting blocks m 1 and m 2 are als

Question

Three blocks are arranged on a horizontal table $ABCD$ as shown in the figure. The strings and pulleys are massless and both the pulleys stand vertical. The strings connecting blocks $m_{1}$ and $m_{2}$ are also vertical and are perpendicular to faces $AB$ and $BC$ which are mutually perpendicular to each other. If $m_{1}$ and $m_{2}$ are $3 kg$ and $4 kg$ respectively. Coefficient of friction between the block $m_{3} = 10 kg$ and the surface is $μ = 0.6$ then, frictional force on $m_{3}$ is

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Answer:

C

Solution:

Net force on $m_{3} = \sqrt{{(30)}^{2} + {(40)}^{2}} = 50 N$

And limiting friction on $m_{3} = μ m_{3} g = 60 N$

$∴$ System remain in equilibrium and friction on $m_{3} = 50 N$

TestHub · Accepted Answer

Net force on m 3 = 30 2 + 40 2 = 50 N And limiting friction on m 3 = μ m 3 g = 60 N ∴ System remain in equilibrium and friction on m 3 = 50 N

Physics - NLM Question with Solution | TestHub

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