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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMEasy2 minQB

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Three blocks of masses $m_{1}, m_{2}$ and $m_{3}$ are placed on a horizontal frictionless surface. A force of 40 N pulls the system then calculate the value of T, if $m_{1} = 10 kg, m_{2} = 6 kg, m_{3} = 4 kg$ -

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Answer:

Solution:

Acceleration of the whole system $a = \frac{F}{m _{1} + m _{2} + m _{3}} = \frac{40}{10 + 6 + 4} = 2 m/ s^{2}$ .

For $m_{1}$ : $40 - T = m_{1} a = 10 \times 2 \Rightarrow T = 20 N$ .

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

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