A body of mass 5 kg under the action of constant force → F = F x 1 ^ + F _ y j ^ has velocity at t = 0 s as → v = ( 6 i ^ − 2 j ^ ) m / s and at t = 10 s as → v = + 6 j ^ m / s . The force → F

Question

A body of mass 5 kg under the action of constant force → F = F x ​ 1 ^ + F _ y j ^ ​ has velocity at t = 0 s as → v = ( 6 i ^ − 2 j ^ ​ ) m / s and at t = 10 s as → v = + 6 j ^ ​ m / s . The force → F is

TestHub · Accepted Answer

Acceleration = change in velocity / time:

$a = \frac{( 6 j ^ ) - ( 6 i ^ - 2 j ^ )}{10} = \frac{- 6 i ^ + 8 j ^}{10} = (- \frac{3}{5} \hat{i} + \frac{4}{5} \hat{j}) m / s^{2}$

$F = m a = 5 (- \frac{3}{5} \hat{i} + \frac{4}{5} \hat{j}) = (- 3 \hat{i} + 4 \hat{j}) N$

Correct option: (4).

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