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Physics - NLM Question with Solution | TestHub

PhysicsNLMFBD & EquilibriumEasy2 minQB

PhysicsEasysingle choice

In the figure shown, initially spring is relaxed. Spring constant of spring is $k = 100 N / m$ . Find minimum value of $μ$ (coefficient of friction) between surface & block so that block remains in equilibrium in final stage :-

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Answer:

Solution:

$x 100 \times 0.25 \times \frac{3}{5} μ = 0.25 m = μ \times (50 - 100 \times 0.25 \times \frac{4}{5}) = \frac{15}{30} = \frac{1}{2} = 0.5$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: QB

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