In an imaginary atmosphere, the air exerts a small force F on any particle in the direction of the particle's motion. A particle of mass m projected upward takes a time t 1 in reaching the maxi

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In an imaginary atmosphere, the air exerts a small force F on any particle in the direction of the particle's motion. A particle of mass m projected upward takes a time t 1 ​ in reaching the maximum height and t 2 ​ in the return journey to the original point. Then:

TestHub · Accepted Answer

Going up, gravity opposes the motion while $F$ assists it, so the retardation is $g - F / m$ ; coming down both act downward, giving acceleration $g + F / m$ .
The slower upward trip takes longer
$t_{1} > t_{2} .$
Option B.
(The result is independent of $m$ only in comparing the two times for the same particle; the inequality itself always holds.)

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