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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMEasy2 minQB

PhysicsEasysingle choice

A horizontal force $F$ is applied at the top of an equilateral triangular block having mass $m .$ The minimum coefficient of friction required to topple the block before translation will be

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Answer:

Solution:

$I = \frac{m a^{2}}{6} + m {(\frac{a}{\sqrt{3}})}^{2} \Rightarrow I = (\frac{m a^{2}}{2})$

$\Rightarrow F \times \frac{a \sqrt{3}}{2} = (m g) \frac{a}{2} \Rightarrow F = (\frac{m g}{\sqrt{3}})$

$F = F_{m a x} \Rightarrow \frac{m g}{\sqrt{3}} μ m g \Rightarrow μ = \frac{1}{\sqrt{3}}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: QB

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