The radius of curvature of each surface of an equiconvex lens is R = 42 c m . Refractive index of the glass = 1.25 . If the final image forms after four internal reflections (But not TIR) inside the l

Question

The radius of curvature of each surface of an equiconvex lens is $R = 42 c m$ . Refractive index of the glass $= 1.25$ . If the final image forms after four internal reflections (But not TIR) inside the lens (for parallel incident beam) calculate the distance of the image from the lens (in cm)

Answer:

4

Solution:

Power of the system $P = 4 P_{M} + 5 P_{L} \frac{1}{f} = \frac{4}{21} + \frac{5}{84}; f = 4 c m$

TestHub · Accepted Answer

Power of the system P = 4 P M ​ + 5 P L ​ f 1 ​ = 21 4 ​ + 84 5 ​ ; f = 4 c m

Physics - Geometrical Optics Question with Solution | TestHub

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JEE Advanced (2028)