For shown situation the value of μ 1 μ 3 is equal to

μ 1 sin 4 5 ∘ = μ 2 sin 3 0 ∘ = μ 3 sin 6 0 ∘ ⇒ μ 1 μ 3 = s i n 6 0 ∘ s i n 4 5 ∘ = 3 2

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PhysicsGeometrical OpticsRefraction at plane surfaceMedium2 minQB

PhysicsMediumsingle choice

For shown situation the value of $\frac{μ _{3}}{μ _{1}}$ is equal to

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Solution:

$μ_{1} sin 4 5^{\circ} = μ_{2} sin 3 0^{\circ} = μ_{3} sin 6 0^{\circ} \Rightarrow \frac{μ _{3}}{μ _{1}} = \frac{s i n 4 5 ^{\circ}}{s i n 6 0 ^{\circ}} = \frac{2}{3}$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface

⏱ 2mℹ️ Source: QB

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