A monkey pulls (along the ground) the mid point of a 10 m long light inextensible string connecting two identical objects A \& B each of mass 0.3 kg continuously along the perpendicular bisector of li

Question

A monkey pulls (along the ground) the mid point of a 10 m long light inextensible string connecting two identical objects A \& B each of mass 0.3 kg continuously along the perpendicular bisector of line joining the masses. The masses are found to approach each other at a relative acceleration of $5 m / s^{2}$ when they are 6 m apart. The constant force applied by monkey is:

Answer:

2.00

Solution:

$T cos 5 3^{\circ} = .3 \times 2.5 = .75$

$T \times \frac{3}{5} = .75 T = 1.25 F = 2 T cos 37 F = 2 \times 1.25 \times \frac{4}{5} = 2 N$

TestHub · Accepted Answer

T cos 5 3 ∘ = .3 × 2.5 = .75 ​ T × 5 3 ​ = .75 ​ T = 1.25 ​ F = 2 T cos 37 ​ F = 2 × 1.25 × 5 4 ​ = 2 N ​

Physics - NLM Question with Solution | TestHub

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