A block of mass m slides down on a wedge of mass M as shown in figure. Let a 1 be the acceleration of the wedge and a 2 the acceleration of block w.r.t. ground. N 1 is the normal reaction betwee

Question

A block of mass m slides down on a wedge of mass M as shown in figure. Let $a_{1}$ be the acceleration of the wedge and $a_{2}$ the acceleration of block w.r.t. ground. $N_{1}$ is the normal reaction between block and wedge and $N_{2}$ the normal reaction between wedge and ground. Friction is absent everywhere. Select the incorrect alternative

TestHub · Accepted Answer

For entire system, F y ​ = ( M + m ) a cmy ​ ​ ( M + m ) g − N = ( M + m ) a cmy ​ ​ N = ( m + M ) ( g − a cmy ​ ) ​ N 1 ​ + ma 1 ​ sin θ = mg cos θ N 1 ​ = m [ g cos θ − a 1 ​ sin θ ] For M :

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