Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minQB

PhysicsMediumsingle choice

A ring of mass m slide from rest on the smooth rod as shown in the figure, due to the block of mass m . Pulley and string are massless. Then find the speed of ring when the string become straight. (Given $θ = 6 0^{\circ}$ )

Options:

Answer:

Solution:

Loss in potential energy $=$ gain in kinetic energy

$\displaylines mg (\frac{h}{cos θ} - h) = \frac{1}{2} mv^{2} m g (\frac{h}{cos 6 0 ^{0}} - h) = \frac{1}{2} m v^{2} v = 2 g h$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...