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PhysicsNLMSimple Application of NLMEasy2 minQB

PhysicsEasysingle choice

An object of mass m is supported by a cord and the tension in the cord is recorded as 0.25 mg . The conclusion that can be drawn is

Answer:

Solution:

Forces: tension $T = 0.25 m g$ up, weight $m g$ down. $m g - T = ma \Rightarrow m g - 0.25 m g = ma \Rightarrow a = 0.75 g$ , directed downward.

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: QB

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