80 railway wagons all of same mass 5 × 10 3 kg are pulled by an engine with a force of 4 × 10 5 N . The tension in the coupling between 30 th and 31 st wagon from the engine is

Railway waygons to be pulled = 80 - 30 = 50 ∴ m = 50 × 5 × 10 3 kg a = F 80 M = 4 × 10 5 80 × 5 × 10 3 ⇒ F 30 = 50 × 5 × 10 3 × 4 × 10 5 80 × 5 × 10 3 = 25 × 10 4 N

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PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

$80$ railway wagons all of same mass $5 \times 10^{3}$ $kg$ are pulled by an engine with a force of $4 \times 10^{5}$ $N$ . The tension in the coupling between $30^{th}$ and $31^{st}$ wagon from the engine is

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Solution:

Railway waygons to be pulled = 80 - 30 = 50

$∴ m = 50 \times 5 \times 10^{3} kg$

$a = \frac{F}{80 M} = \frac{4 \times 10^{5}}{80 \times 5 \times 10^{3}}$

$\Rightarrow F_{30} = 50 \times 5 \times 10^{3} \times \frac{4 \times 10^{5}}{80 \times 5 \times 10^{3}}$ $= 25 \times 10^{4} N$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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