Physics - NLM Question with Solution | TestHub

If man A starts climbing up on the ladder with a constant acceleration of $4\mathrm{m}/{\mathrm{s}}^2$ w.r.t. ground and C is at rest w.r.t. rope. Then the vertical distance between A and C after 1 sec is 1m.

If man C starts climbing up on the rope (while A remain at rest w.r.t ladder) with a constant acceleration of $4\mathrm{m}/{\mathrm{s}}^2$ w.r.t. ground then the vertical distance between A and C after 1 sec is 2 m.

If both man A and C start climbing up with a constant acceleration of $4\mathrm{m}/{\mathrm{s}}^2$ w.r.t. ground then the acceleration of ladder is $4\mathrm{m}/{\mathrm{s}}^2$ upward.

If both man A and C start climbing up with a constant acceleration of $4\mathrm{m}/{\mathrm{s}}^2$ w.r.t. ground then the acceleration of ladder is $3\mathrm{m}/{\mathrm{s}}^2$ upward.