A force F is applied on a block of mass 3 kg which rests on a horizontal surface with a coefficient of friction 1 2 3 . The maximum value of F for which the block doesn't move, is [Take g = 10 m

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A force F is applied on a block of mass 3 kg which rests on a horizontal surface with a coefficient of friction 1 2 3 . The maximum value of F for which the block doesn't move, is [Take g = 10 m s - 2 ]

TestHub · Accepted Answer

From acting on block are shown in adjoining figure

As the block does not move, hence

$F \cos 60 ° = f = μ N = μ (M g + F \sin 60 °)$

$∴ F \frac{1}{2} = \frac{1}{2 \sqrt{3}} (\sqrt{3} \times 10 + F \cdot \frac{\sqrt{3}}{2})$

On simplification, we get $F = 20$ N

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