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PhysicsNLMFrictionEasy2 minPYQ_2022

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A system of two blocks of masses $m = 2 kg$ and $M = 8 kg$ is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is $0.5$ . The maximum horizontal force $F$ that can be applied to the block of mass $M$ so that the blocks move together will be $(g = 9.8 m s^{- 2})$

Options:

Answer:

Solution:

Maximum acceleration of the upper block will be,

$a_{m a x} = μ g = 0.5 \times 9.8 = 4.9 m s^{- 2}$

Therefore, maximum force that can be applied on the lower block is,

$F_{\max} = (2 + 8) \times 4.9 = 49 N$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: PYQ_2022

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