Physics - NLM Question with Solution | TestHub

$500g-T=500a \dots \dots (1)$
$T-100g\sin 30°-T^{\prime \prime }=100a$
Or, $T-T^{\prime \prime }-50g=100a \dots \dots (2)$

Again, $T^{\prime \prime }-50g=50a \dots \dots (3)$

From equations (2) and (3),
$T-100g=150a \dots \dots (4)$

Adding equations (1) and (4), $400g=650a$ or $a=\frac{400g}{650}=\frac{8g}{13}$
This acceleration is downwards.