Physics - NLM Question with Solution | TestHub

Given forces are $F_1=8$ N and $F_2=6$ N acting perpendicular to each other.

The magnitude of the net force is $F=\sqrt{F_1^2+F_2^2}=\sqrt{8^2+6^2}=10$ N.

The magnitude of acceleration is $a=\frac{F}{m}=\frac{10}{5}=2$ m s${}^{-2}$.

Let $\theta$ be the angle made by the net force with the $8$ N force.

$\tan \theta =\frac{F_2}{F_1}=\frac{6}{8}=\frac{3}{4}$

$\theta ={\tan }^{-1}\left(\frac{3}{4}\right)$ with the $8$ N force.

Answer: $2$ m s${}^{-2}$; ${\tan }^{-1}(3/4)$ with $8$ N force