The weight of man in a stationary lift is w 1 and when it is moving downwards with uniform acceleration ' a ' is w 2 . If the ratio w 1 : w 2 = 4 : 3 , then the value of ' a &#0

Question

The weight of man in a stationary lift is w 1 ​ and when it is moving downwards with uniform acceleration ' a ' is w 2 ​ . If the ratio w 1 ​ : w 2 ​ = 4 : 3 , then the value of ' a ' is ( g = acceleration due to gravity)

TestHub · Accepted Answer

The weight of the man in a stationary lift is $w_{1} = m g$ .

The apparent weight of the man when the lift is moving downwards with uniform acceleration $a$ is $w_{2} = m (g - a)$ .

Given that $\frac{w _{1}}{w _{2}} = \frac{4}{3}$ .

Substituting the values, we get $\frac{m g}{m ( g - a )} = \frac{4}{3}$ .

$\frac{g}{g - a} = \frac{4}{3}$

$3 g = 4 g - 4 a$

$4 a = g$

$a = \frac{g}{4}$

Answer: $\frac{g}{4}$

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