Three blocks of masses m 1 , m 2 and m 3 are connected to a massless string on a frictionless table as shown in the figure. They are pulled with a force of 40 N. If m 1 = 10 kg , m 2 = 6 kg and m 3 =

Question

Three blocks of masses m 1 , m 2 and m 3 are connected to a massless string on a frictionless table as shown in the figure. They are pulled with a force of 40 N. If m 1 = 10 kg , m 2 = 6 kg and m 3 = 4 kg , then tension T 2 will be

TestHub · Accepted Answer

Since, the table is frictionless, i.e., it is smooth, therefore, force on the block is given by

$F = (m_{1} + m_{2} + m_{3}) a$

$\Rightarrow a = \frac{F}{m_{1} + m_{2} + m_{3}}$

$\Rightarrow a = \frac{40}{10 + 6 + 4} = \frac{40}{20} = 2 m s^{- 2}$

Now, the tension between 10 kg and 6 kg masses is given by

$T_{2} = (m_{2} + m_{3}) a$

$= (4 + 6) 2 = 10 \times 2$

$T_{2} = 20 N$

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