Three blocks A , B and C are pulled on a horizontal smooth surface by a force of 80 N as shown in figure. The tensions T 1 and T 2 in the string are respectively:

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Since, the length of the string will remain same. Hence, all blocks will have the same acceleration.
$a_{A} = a_{B} = a_{C} = \frac{F}{5 + 3 + 2} = \frac{80}{10} = 8 m s^{- 2}$
Therefore, $T_{1} = 5 \times 8 = 40 N$ .
Now,
$T_{2} - T_{1} = 3 \times 8 \Rightarrow T_{2} = 64 N$

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