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PhysicsNLMFBD & EquilibriumEasy2 minPYQ_2022

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A block of metal weighing $2 kg$ is resting on a frictionless plane (as shown in figure). It is struck by a jet releasing water at a rate of $1 kg s^{- 1}$ and at a speed of $10 {m s}^{- 1}$ . Then, the initial acceleration of the block, in $m s^{- 2}$ , will be

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Answer:

Solution:

Let velocity of water jet be $v$ .

So, force applied is $F = \frac{Δ p}{Δ t} = \frac{(∆ m v)}{Δ t}$

$\Rightarrow m a = \frac{(∆ m v)}{Δ t}$

Acceleration of block, $a = \frac{1 \times 10}{2}$

$a = 5 m s^{- 2}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: PYQ_2022

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