A force F → = ( 40 i ^ + 10 j ^ ) N acts on a body of mass 5 kg . If the body starts from rest, its position vector r → at time t = 10 s will be

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d v → d t = a → = F → m = ( 8 i ^ + 2 j ^ ) m s - 2 d r → dt = v → = ( 8 t i ^ + 2 t j ^ ) m s - 1 r → = ( i ^ + 2 j ^ ) t 2 2 m At t = 10 sec r → = [ ( 8 i ^ + 2 j ^ ) 50 ] m ⇒ r → = ( 400 i ^ + 100 j ^ ) m

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