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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMEasy2 minPYQ_2021

PhysicsEasysingle choice

A force $\vec{F} = (40 \hat{i} + 10 \hat{j}) N$ acts on a body of mass $5 kg$ . If the body starts from rest, its position vector $\vec{r}$ at time $t = 10 s$ will be

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Answer:

Solution:

$\frac{d \vec{v}}{d t} = \vec{a} = \frac{\vec{F}}{m} = (8 \hat{i} + 2 \hat{j}) m s^{- 2}$

$\frac{d \vec{r}}{dt} = \vec{v} = (8 t \hat{i} + 2 t \hat{j}) m s^{- 1}$

$\vec{r} = (\hat{i} + 2 \hat{j}) \frac{t^{2}}{2} m$

At $t = 10 \sec$

$\vec{r} = [(8 \hat{i} + 2 \hat{j}) 50] m$

$\Rightarrow \vec{r} = (400 \hat{i} + 100 \hat{j}) m$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: PYQ_2021

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