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PhysicsNLMSimple Application of NLMMedium2 minQB

PhysicsMediumsingle choice

A 20 gm ball hits a wall normally at 10 m/s and rebounds at 5 m/s; the contact lasts 0.02 s. The average force on the ball is:

Answer:

Solution:

$Δ p = 0.02 \times (10 - (- 5)) = 0.3$
N s, so
$F = \frac{0.3}{0.02} = 15 N .$
Option B.

Subject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: QB

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