Physics - NLM Question with Solution | TestHub

Maximum tension in the string T = mg

= 30 x 10

= 300 N



T - mg = ma

From the figure

300 - 10 x 10 = 10a

$\therefore$a = 20 m s^-2

Thus, the maximum acceleration with which the stone can be raised is 20 m s^-2.

Given,     s = 10 m

and         u = 0

$\therefore$$10=\frac{1}{2}\left(20\right){\text{t}}^2$

$\Rightarrow$t = 1 s