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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle is moving on rough horizontal ground with an initial velocity $v_{0}$ . If ${\frac{3}{4}}^{t h}$ of its kinetic energy is lost due to friction in time $t_{0}$ , then the coefficient of friction between the particle and the ground is

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Answer:

Solution:

${\frac{3}{4}}^{t h}$ energy is lost i.e., ${\frac{1}{4}}^{t h}$ kinetic energy is left.

Hence, its velocity becomes $\frac{v_{0}}{2}$ under a retardation of $μ g$ in time $t_{0}$ .

$∴$ From the first equation of motion,

$\frac{v_{0}}{2} = v_{0} - μ g t_{0}$

or $μ g t_{0} = \frac{v_{0}}{2}$

or $μ = \frac{v_{0}}{2 g t_{0}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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