Physics - NLM Question with Solution | TestHub

Pressure at the bottom of the tank is given by$\mathrm{P}=\mathrm{h\rho g}{=3\times 10}^5 \mathrm{N} {\mathrm{m}}^{-2}$and velocity of water is given by$\mathrm{v}=\sqrt{2\mathrm{gh}}$.

$\therefore \text{v}=\sqrt{\frac{2\text{P}}{\mathrm{\rho }}}=\sqrt{\frac{2\times 3\times 10^5}{10^3}}=\sqrt{600}\text{m}/\text{s}$