A conveyor belt is moving at a constant speed of 2 m / s . A box is gently dropped on it. The coefficient of friction between them is μ = 0.5 . The distance that the box will move relative to belt bef

Question

A conveyor belt is moving at a constant speed of 2 m / s . A box is gently dropped on it. The coefficient of friction between them is μ = 0.5 . The distance that the box will move relative to belt before coming to rest on it taking g = 10 ms − 2 , isNEET 2011 (Mains)

TestHub · Accepted Answer

Force, F = μ m g Retardation of the block on the belt a = m F ​ = m μ m g ​ = μg From, v 2 0 s ​ = u 2 + 2 a s = ( 2 ) 2 − 2 ( μg ) s = 2 × 0.5 × 10 4 ​ = 0.4 m ​

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