Consider a car moving along a straight horizontal road with a speed of 72 km h - 1 . If the coefficient of static friction between the tyres and the road is 0 . 5 , the shortest distance in which the

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Consider a car moving along a straight horizontal road with a speed of 72 km h - 1 . If the coefficient of static friction between the tyres and the road is 0 . 5 , the shortest distance in which the car can be stopped is (taking g = 10 m s - 2 )

TestHub · Accepted Answer

Here u = 72 km h - 1 = 20 m s - 1 ; v = 0 ; a = - μ g = - 0.5 × 10 = - 5 m s - 2 As v 2 = u 2 + 2 a s , ∴ s = v 2 - u 2 2 a = ( 0 - 20 2 ) 2 × - 5 = 40 m

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