A rope of length 10 m and linear density 0 . 5 kg m - 1 is lying length wise on a smooth horizontal floor. It is pulled by a force of 25 N . The tension in the rope at a point 6 m away from the point

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A rope of length 10 m and linear density 0 . 5 kg m - 1 is lying length wise on a smooth horizontal floor. It is pulled by a force of 25 N . The tension in the rope at a point 6 m away from the point of application is

TestHub · Accepted Answer

Mass of rope = 10 × 0.5 = 5 kg Given force = 25 N Acceleration = F m = 25 5 = 5 m s - 2 Length of remaining rope = 4 m Hence mass of remaining rope = 4 × 0.5 = 2 kg Hence tension on the rope at a point 6m away = m × a = 2 × 5 = 10 N

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