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PhysicsNLMFBD & EquilibriumMedium2 minQB

PhysicsMediuminteger

Consider the two configurations shown in equilibrium. Find ratio of $T_{A} / T_{B}$ . (Ignore the mass of the rope and the pulley)

$T_{A} / T_{B}$

Answer:

Solution:

Configuration A (fixed pulley): $T_{A} = M g$

Configuration B (movable pulley): $2 T_{B} = M g \Rightarrow T_{B} = \frac{M g}{2}$

$\frac{T _{A}}{T _{B}} = \frac{M g}{M g /2} = 2$

Subject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: QB

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